EC-COUNCIL 312-49 PDF

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Exam Code: 312-49
Exam Name: EC-COUNCIL (Computer Hacking Forensic Investigator )
One year free update, No help, Full refund!
Total Q&A: 150 Questions and Answers
Last Update: 2013-11-18

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NO.1 The offset in a hexadecimal code is:
A. The last byte after the colon
B. The 0x at the beginning of the code
C. The 0x at the end of the code
D. The first byte after the colon
Answer: B

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NO.2 A(n) _____________________ is one that's performed by a computer program rather than the
attacker manually performing the steps in the attack sequence.
A. blackout attack
B. automated attack
C. distributed attack
D. central processing attack
Answer: B

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NO.3 What file structure database would you expect to find on floppy disks?
A. NTFS
B. FAT32
C. FAT16
D. FAT12
Answer: D

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NO.4 What type of attack occurs when an attacker can force a router to stop forwarding packets by
flooding the router with many open connections simultaneously so that all the hosts behind the
router are effectively disabled?
A. digital attack
B. denial of service
C. physical attack
D. ARP redirect
Answer: B

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NO.5 The newer Macintosh Operating System is based on:
A. OS/2
B. BSD Unix
C. Linux
D. Microsoft Windows
Answer: B

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NO.6 What does the superblock in Linux define?
A. file system names
B. available space
C. location of the first inode
D. disk geometry
Answer: B, C, D

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NO.7 When an investigator contacts by telephone the domain administrator or controller listed by a
whois lookup to request all e-mails sent and received for a user account be preserved, what
U.S.C. statute authorizes this phone call and obligates the ISP to preserve e-mail records?
A. Title 18, Section 1030
B. Title 18, Section 2703(d)
C. Title 18, Section Chapter 90
D. Title 18, Section 2703(f)
Answer: D

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NO.8 When examining the log files from a Windows IIS Web Server, how often is a new log file
created?
A. the same log is used at all times
B. a new log file is created everyday
C. a new log file is created each week
D. a new log is created each time the Web Server is started
Answer: A

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NO.9 When examining a file with a Hex Editor, what space does the file header occupy?
A. the last several bytes of the file
B. the first several bytes of the file
C. none, file headers are contained in the FAT
D. one byte at the beginning of the file
Answer: D

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NO.10 You are working for a large clothing manufacturer as a computer forensics investigator and are
called in to investigate an unusual case of an employee possibly stealing clothing designs from
the company and selling them under a different brand name for a different company. What you
discover during the course of the investigation is that the clothing designs are actually original
products of the employee and the company has no policy against an employee selling his own
designs on his own time. The only thing that you can find that the employee is doing wrong is that
his clothing design incorporates the same graphic symbol as that of the company with only the
wording in the graphic being different. What area of the law is the employee violating?
A. trademark law
B. copyright law
C. printright law
D. brandmark law
Answer: A

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NO.11 It takes _____________ mismanaged case/s to ruin your professional reputation as a computer
forensics examiner?
A. by law, three
B. quite a few
C. only one
D. at least two
Answer: C

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NO.12 A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is
an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the
attacker by studying the log. Please note that you are required to infer only what is explicit in the
excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting,
basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84
Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104
Len: 1084
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............
00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ...............
3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.